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Choose the Best Answer · Q2

Q.An element X has the following isotopic composition: ²⁰⁰X = 90%, ¹⁹⁹X = 8% and ²⁰²X = 2%. The weighted average atomic mass of the element X is closest to

(a) 201 u
(b) 202 u
(c) 199 u
(d) 200 u
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Step 1. Weighted average atomic mass = (200×0.90) + (199×0.08) + (202×0.02).

Step 2. = 180.00 + 15.92 + 4.04 = 199.96 u.

Step 3. 199.96 u rounds to the closest option, 200 u.

✓Final answer

200 u

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