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Chemistry · Ch 9 — Solutions

Non-ideal Solutions: Positive and Negative Deviations from Raoult's Law

9.8.2

Non-ideal Solutions: Positive and Negative Deviations from Raoult's Law

A non-ideal solution fails to obey Raoult's law across the whole concentration range, and unlike an ideal solution, it shows a measurable change in both enthalpy and volume on mixing: ΔHmixing≠0\Delta H_{mixing}\ne0 and ΔVmixing≠0\Delta V_{mixing}\ne0. Depending on how the A-B intermolecular attraction compares with the A-A and B-B attractions, the deviation from Raoult's law can go one of two ways.

Positive deviation. Suppose the attractive forces between A and B molecules are weaker than the attractive forces within pure A (A-A) or pure B (B-B). Molecules in such a mixture then have a greater tendency to escape into the vapour phase than an ideal A-B mixture would -- so each component's actual partial pressure exceeds what Raoult's law predicts:

pA>pA∘xAandpB>pB∘xBp_A > p^\circ_Ax_A \qquad\text{and}\qquad p_B > p^\circ_Bx_B

and consequently the total vapour pressure is higher than Raoult's law predicts:

ptotal>pA∘xA+pB∘xB(9.19)p_{total} > p^\circ_Ax_A + p^\circ_Bx_B \qquad (9.19)

This is called positive deviation (Figure 9.7): the actual vapour-pressure curves for A, B and the total all lie above the dashed ideal (Raoult's-law) lines.

Worked example -- ethanol and water. In an ethanol-water mixture, the hydrogen bonding between ethanol and water molecules is weaker than the hydrogen bonding among ethanol molecules themselves, or among water molecules themselves. This weaker cross-interaction means both components evaporate more readily from the mixture than expected, raising the solution's vapour pressure above the Raoult's-law prediction. Mixing is endothermic (ΔHmixing>0\Delta H_{mixing}>0) and there is a slight increase in volume on mixing (ΔVmixing>0\Delta V_{mixing}>0). Other positive-deviation pairs given in the text: ethyl alcohol & cyclohexane, benzene & acetone, carbon tetrachloride & chloroform, acetone & ethyl alcohol, and ethyl alcohol & water.

Negative deviation. Now suppose the A-B attractive forces are stronger than the A-A and B-B forces. Molecules then have a lower escaping tendency than an ideal mixture would show, so

pA<pA∘xAandpB<pB∘xBp_A < p^\circ_Ax_A \qquad\text{and}\qquad p_B < p^\circ_Bx_B

and the total vapour pressure is lower than the sum pA∘xA+pB∘xBp^\circ_Ax_A+p^\circ_Bx_B predicts -- negative deviation (Figure 9.8): the actual curves lie below the ideal dashed lines. …

Figure 9.7Positive deviation from Raoult's law

What this figure shows. Vapour pressure (y-axis) plotted against mole fraction (x-axis, xA=1x_A=1 at left to xA=0/xB=1x_A=0/x_B=1 at right). Dotted straight lines show the ideal (Raoult's-law-predicted) partial pressures of A and B; solid curved lines show the actual partial pressures of A, B and the total (P=PA+PBP=P_A+P_B), both of which bulge ABOVE their ideal dotted lines across the composition range -- illustrating that the real vapour pressure of each component, and hence the total, exceeds the Raoult's-law predic …

Figure 9.8Negative deviation from Raoult's law

What this figure shows. Vapour pressure (y-axis) plotted against mole fraction (x-axis, xA=1x_A=1 at left to xB=1x_B=1 at right). Dotted straight lines show the ideal partial pressures of A and B; solid curved lines for the actual partial pressures of A, B and total (P=PA+PBP=P_A+P_B) dip BELOW their ideal dotted lines, illustrating that the real total vapour pressure is lower than the Raoult's-law prediction (annotated for th …