Skip to content

Chemistry · Ch 9 — Solutions

Osmosis and Osmotic Pressure

9.9.4

Osmosis and Osmotic Pressure

Osmosis is a spontaneous process central to many biological systems: solvent molecules pass through a semipermeable membrane, moving from a solution of lower solute concentration into a solution of higher solute concentration. The name comes from the Greek word osmos, meaning "to push." A semipermeable membrane selectively allows only certain molecules to pass through it while blocking others.

The classic apparatus (Figure 9.13). A semipermeable membrane divides a chamber into two compartments. Pure water is placed in one compartment and aqueous NaCl solution in the other, with both liquid levels initially equal. Because the two sides differ in concentration, water molecules move from the pure-water side into the NaCl-solution side through the membrane (the membrane passes water in either direction but blocks NaCl entirely). This net inward flow of water into the salt-solution side increases its volume, which dilutes it (lowering its concentration) and simultaneously builds up a pressure difference between the two compartments. That growing pressure difference eventually pushes some water molecules back toward the pure-solvent side, until the rates of movement in both directions become exactly equal -- an equilibrium. The pressure difference at this equilibrium is called the osmotic pressure (π\pi), which can equivalently be defined as: "the pressure that must be applied to the solution side to just stop the net inward flow of solvent (to stop osmosis) through the semipermeable membrane."

The van't Hoff equation. Van't Hoff found that, for dilute solutions, osmotic pressure is directly proportional to both the solute's molar concentration and the absolute temperature:

π=cRT(9.31)\pi = cRT \qquad (9.31)

where cc is the concentration in molarity, TT is the absolute temperature, and RR is the gas constant. This has exactly the same mathematical form as the ideal gas equation, and is called the van't Hoff equation for dilute solutions.

Determining molar mass from osmotic pressure. Since c=n/Vc=n/V, equation 9.31 can be rewritten π=nRTV\pi=\dfrac{nRT}{V}, i.e.

πV=nRT(9.32)\pi V = nRT \qquad (9.32)

For wBw_B g of nonvolatile solute (molar mass MBM_B) dissolved to give a solution of volume VV, n=wB/MBn=w_B/M_B; substituting into 9.32 and rearranging,

MB=wB RTπ V(9.33)M_B = \frac{w_B\,RT}{\pi\,V} \qquad (9.33)

so the molar mass can be found once the osmotic pressure of a solution of known mass and volume has been measured.

Worked example (Example Problem 6). At 400 K, 1.5 g of an unknown substance is dissolved and the solution made up to 1.5 L; its osmotic pressure is 0.3 bar. Using R=8.314×10−2R=8.314\times10^{-2} L bar mol−1^{-1} K−1^{-1}:

M=w×RTπ×V=1.5×8.314×10−2×4000.3×1.5=110.85 g mol−1M = \frac{w\times RT}{\pi\times V} = \frac{1.5\times8.314\times10^{-2}\times400}{0.3\times1.5} = 110.85\ \text{g mol}^{-1}

Why osmotic pressure is favoured over the other three colligative properties. Its magnitude is comparatively large, even for very dilute solutions -- compare this against boiling-point elevation and freezing-point depression, where even a full 1-molal aqueous solution only elevates the boiling point by 0.512∘^\circC and depresses the freezing point by 1.86∘^\circC. Because osmotic pressure can be measured conveniently at room temperature, it is especially valuable for determining the molar mass of biomolecules that would denature or degrade at the higher temperatures a boiling-point measurement would need. …

Figure 9.13Osmosis and osmotic pressure

What this figure shows. A U-shaped or two-compartment apparatus with a semipermeable membrane separating pure water (left) from an aqueous NaCl solution (right), both initially at the same liquid level. Water molecules are shown crossing the membrane preferentially from the pure-water side to the solution side (net flow toward higher concentration), raising the liquid level on the solution side -- illustrating osmosis and the pressure difference that …

Figure 9.14Isotonic solutions

What this figure shows. A diagram of two solutions of equal osmotic pressure separated by a semipermeable membrane, with equal-sized arrows drawn in both directions across the membrane, indicating equal solvent flow each way and hence zero net flow between two i …

Misc 9.9.4-ict-osmosisICT Corner: Osmosis simulation

Worked out. A QR-code/URL box pointing to an online PhET-style simulation (pbslm-contrib WGBH ARCT15 SimBucket) that visualises osmosis across a semipermeable membrane: a left box holds pure solvent, a right box holds solution, and separate counters show the changing number of water molecules on each side as the simulation runs, letting students watch net water flow toward the more concentrated …

Misc Example Problem 6Molar mass of an unknown solute from osmotic pressure

Worked out. At 400 K, 1.5 g of an unknown substance dissolved and made up to 1.5 L exerts an osmotic pressure of 0.3 bar. Using M=w×RTπ×VM=\dfrac{w\times RT}{\pi\times V} (R = 8.314×10−28.314\times10^{-2} L bar mol−1^{-1} K−1^{-1}): M=1.5×8.314×10−2×4000.3×1.5=110.85 g mol−1M=\dfrac{1.5\times8.314\times10^{-2}\times400}{0.3\times1.5}=110.85\ \text{g mol}^{-1}. …

Misc Evaluate Yourself 13Mass of glucose isotonic with a urea solution

Worked out. An in-text practice box: what is the mass of glucose (C6_6H12_{12}O6_6) in one litre of solution that is isotonic with 6 g L−1^{-1} of urea (NH2_2CONH2_2)? …