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Question 84 of 92

Q.Calculate the entropy change during the melting of one mole of ice into water at 0°C and 1 atm pressure. Enthalpy of Fusion of ice is 6008 J mol^-1.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2023Subjective· 2mImportance★★★★★
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For melting at constant temperature and pressure, Delta-S = Delta-H(fusion)/T; using Delta-H(fusion) = 6008 J/mol and T = 273 K gives Delta-S about 22.01 J K^-1 mol^-1.

At the melting point, ice and water coexist in equilibrium at constant temperature and pressure, so the process is reversible, and the entropy change of fusion is given by:

Delta-S(fusion) = Delta-H(fusion) / T

Given:

Delta-H(fusion) = 6008 J mol^-1

T = 0 degree C = 273 K (273.15 K, commonly rounded to 273 K)

Delta-S(fusion) = 6008 / 273 = 22.007 J K^-1 mol^-1, about 22.01 J K^-1 mol^-1

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