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Exercise 2.6 · Q4

Q.Solve (2x+1)2−(3x+2)2=0(2x+1)^2-(3x+2)^2=0.

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Step 1. With A=2x+1,B=3x+2A=2x+1,B=3x+2: A2−B2=(A−B)(A+B)=0A^2-B^2=(A-B)(A+B)=0.

Step 2. A−B=(2x+1)−(3x+2)=−x−1A-B=(2x+1)-(3x+2)=-x-1. A+B=(2x+1)+(3x+2)=5x+3A+B=(2x+1)+(3x+2)=5x+3. …

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