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Question 126 of 128

Q.If x=−2x = -2 is one root of x3−x2−17x=22x^3 - x^2 - 17x = 22, then find the other roots of the equation.

Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2026Subjective· 2mImportance★★★★★
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Dividing x3−x2−17x−22x^3-x^2-17x-22 by (x+2)(x+2) gives the quotient x2−3x−11x^2-3x-11, whose roots via the quadratic formula are 3±532\dfrac{3\pm\sqrt{53}}{2}.

The equation is x3−x2−17x=22x^3-x^2-17x=22, i.e. x3−x2−17x−22=0x^3-x^2-17x-22=0.

Since x=−2x=-2 is a root, (x+2)(x+2) is a factor. Divide:

x3−x2−17x−22÷(x+2)=x2−3x−11x^3-x^2-17x-22 \div (x+2) = x^2-3x-11

(Check: (x+2)(x2−3x−11)=x3−3x2−11x+2x2−6x−22=x3−x2−17x−22(x+2)(x^2-3x-11)=x^3-3x^2-11x+2x^2-6x-22=x^3-x^2-17x-22 ✓)

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