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Exercise 2.7 · Q2

Q.If x2+x+1x^2+x+1 is a factor of the polynomial 3x3+8x2+8x+a3x^3+8x^2+8x+a, then find the value of aa.

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Step 1. Divide 3x3+8x2+8x+a3x^3+8x^2+8x+a by x2+x+1x^2+x+1: 3x3÷x2=3x3x^3\div x^2=3x; 3x(x2+x+1)=3x3+3x2+3x3x(x^2+x+1)=3x^3+3x^2+3x.

Step 2. Subtract: (3x3+8x2+8x+a)−(3x3+3x2+3x)=5x2+5x+a(3x^3+8x^2+8x+a)-(3x^3+3x^2+3x)=5x^2+5x+a.

Step 3. Continue: 5x2÷x2=55x^2\div x^2=5; 5(x2+x+1)=5x2+5x+55(x^2+x+1)=5x^2+5x+5. Subtract: (5x2+5x+a)−(5x2+5x+5)=a−5(5x^2+5x+a)-(5x^2+5x+5)=a-5. …

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