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Exercise 2.7 · Q1

Q.Factorize: x4+1x^4+1. (Hint: Try completing the square.)

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Concept understanding — Polynomial Identities and Factorization

A library of standard identities (valid for all real x,a,bx,a,b, and n∈Nn\in N where noted) is the main tool for factoring polynomials and constructing them from given conditions:

(x±a)3=x3±3x2a+3xa2±a3,x3+a3=(x+a)(x2−xa+a2),x3−a3=(x−a)(x2+xa+a2),(x\pm a)^3=x^3\pm3x^2a+3xa^2\pm a^3,\qquad x^3+a^3=(x+a)(x^2-xa+a^2),\qquad x^3-a^3=(x-a)(x^2+xa+a^2),

xn−an=(x−a)(xn−1+xn−2a+⋯+an−1),xn+bn=(x+b)(xn−1−xn−2b+⋯+(−b)n−1) (n∈N).x^n-a^n=(x-a)(x^{n-1}+x^{n-2}a+\cdots+a^{n-1}),\qquad x^n+b^n=(x+b)(x^{n-1}-x^{n-2}b+\cdots+(-b)^{n-1})\ (n\in N).

Completing the square to factor. A quartic like x4+1x^4+1 has no rational linear/quadratic factor directly, but adding and subtracting 2x22x^2 turns it into a difference of squares (x2+1)2−(2x)2(x^2+1)^2-(\sqrt2x)^2, which then factors normally.

Method of undetermined coefficients. To construct a polynomial from given zeros and/or function values: write it with unknown coefficients (or, if the zeros are already known, in factored form with one unknown overall scale constant), then use 'equal polynomials have equal same-power coefficients' (or substitute the given conditions directly) to solve for the unknowns. This same coefficient-matching idea proves polynomial-divisibility identities (matching a quotient's unknown coefficients) and derives closed forms for sums like 1+2+⋯+n=n(n+1)21+2+\cdots+n=\dfrac{n(n+1)}2 by positing a polynomial form for the sum and matching how it changes from nn to n+1n+1.

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