Skip to content
Exercise 10.2 · Q14

Q.Find the derivative of the following function with respect to the corresponding independent variable: y=cosec⁡x⋅cot⁡xy = \operatorname{cosec} x \cdot \cot x

Puducherry TnboardTextbookSubjectiveImportance★★★★★
15% · 21/143 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Identify u=cosec⁡xu = \operatorname{cosec}x, v=cot⁡xv = \cot x, so u′=−cosec⁡xcot⁡xu' = -\operatorname{cosec}x\cot x, v′=−cosec⁡2xv' = -\operatorname{cosec}^2x.

Step 2. Apply the product rule: y′=(−cosec⁡xcot⁡x)(cot⁡x)+(cosec⁡x)(−cosec⁡2x)y' = (-\operatorname{cosec}x\cot x)(\cot x) + (\operatorname{cosec}x)(-\operatorname{cosec}^2x).

Step 3. Simplify: y′=−cosec⁡xcot⁡2x−cosec⁡3xy' = -\operatorname{cosec}x\cot^2x - \operatorname{cosec}^3x. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.