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Exercise 10.2 · Q15

Q.Find the derivative of the following function with respect to the corresponding independent variable: y=xsin⁡xcos⁡xy = x \sin x \cos x

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Step 1. Identify u=xu=x, v=sin⁡xv=\sin x, w=cos⁡xw=\cos x, so u′=1u'=1, v′=cos⁡xv'=\cos x, w′=−sin⁡xw'=-\sin x.

Step 2. Apply the extended product rule y′=u′vw+uv′w+uvw′y' = u'vw + uv'w + uvw': y′=(1)(sin⁡x)(cos⁡x)+x(cos⁡x)(cos⁡x)+x(sin⁡x)(−sin⁡x)y' = (1)(\sin x)(\cos x) + x(\cos x)(\cos x) + x(\sin x)(-\sin x).

Step 3. Simplify: y′=sin⁡xcos⁡x+xcos⁡2x−xsin⁡2x=sin⁡xcos⁡x+x(cos⁡2x−sin⁡2x)y' = \sin x\cos x + x\cos^2 x - x\sin^2 x = \sin x\cos x + x(\cos^2x - \sin^2x). …

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