Skip to content
Exercise 11.3 · Q4

Q.Integrate the following with respect to xx:
[!FORMULA] 81−(4x)2+271−9x2−151+25x2\dfrac{8}{\sqrt{1-(4x)^{2}}}+\dfrac{27}{\sqrt{1-9x^{2}}}-\dfrac{15}{1+25x^{2}}

Puducherry TnboardTextbookSubjectiveImportance★★★★★
10% · 13/129 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Decompose into three terms, matching 9x2=(3x)29x^2=(3x)^2 and 25x2=(5x)225x^2=(5x)^2 to the standard sin⁡−1\sin^{-1}/tan⁡−1\tan^{-1} forms, then integrate each with its leading coefficient.

Step 1. First term. Already 1−(4x)21-(4x)^2, a=4a=4:

∫81−(4x)2 dx=8×14sin⁡−1(4x)+c=2sin⁡−1(4x)+c.\int \frac{8}{\sqrt{1-(4x)^2}}\,dx = 8\times\frac14\sin^{-1}(4x)+c=2\sin^{-1}(4x)+c.

Step 2. Second term. 9x2=(3x)29x^2=(3x)^2, a=3a=3:

∫271−9x2 dx=27×13sin⁡−1(3x)+c=9sin⁡−1(3x)+c.\int \frac{27}{\sqrt{1-9x^2}}\,dx = 27\times\frac13\sin^{-1}(3x)+c=9\sin^{-1}(3x)+c.

Step 3. Third term. 25x2=(5x)225x^2=(5x)^2, a=5a=5:

∫151+25x2 dx=15×15tan⁡−1(5x)+c=3tan⁡−1(5x)+c,\int \frac{15}{1+25x^2}\,dx = 15\times\frac15\tan^{-1}(5x)+c=3\tan^{-1}(5x)+c,

and since this term is subtracted in the original expression,

−∫151+25x2 dx=−3tan⁡−1(5x)+c.-\int \frac{15}{1+25x^2}\,dx = -3\tan^{-1}(5x)+c.

Step 4. Combine.

2sin⁡−1(4x)+9sin⁡−1(3x)−3tan⁡−1(5x)+c.2\sin^{-1}(4x)+9\sin^{-1}(3x)-3\tan^{-1}(5x)+c. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.