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Exercise 11.6 · Q11

Q.1xlog⁡xlog⁡(log⁡x)\dfrac{1}{x\log x\log(\log x)}

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A double application of the "derivative of a log is 1 over the argument" pattern: differentiating log⁡(log⁡x)\log(\log x) produces exactly 1xlog⁡x\frac{1}{x\log x}.

Step 1. Substitute. Let u=log⁡(log⁡x)u=\log(\log x), so du=1log⁡x⋅1x dx=dxxlog⁡xdu=\dfrac1{\log x}\cdot\dfrac1x\,dx=\dfrac{dx}{x\log x}.

Step 2. Rewrite. ∫dxxlog⁡xlog⁡(log⁡x)=∫duu\displaystyle\int\dfrac{dx}{x\log x\log(\log x)}=\int\dfrac{du}{u}.

Step 3. Integrate. log⁡∣u∣+c\log|u|+c. …

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