Skip to content
Exercise 12.3 · Q8

Q.One bag contains 5 white and 3 black balls. Another bag contains 4 white and 6 black balls. If one ball is drawn from each bag, find the probability that

(i) both are white
(ii) both are black
(iii) one white and one black.
Puducherry TnboardTextbookSubjectiveImportance★★★★★
27% · 24/89 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Given. Bag 1: 5 white, 3 black (8 total). Bag 2: 4 white, 6 black (10 total). One ball drawn from each bag, independently.

Step 2. Part (i) -- both white. P=58×410=2080=14P=\dfrac58\times\dfrac4{10}=\dfrac{20}{80}=\dfrac14.

Step 3. Part (ii) -- both black. P=38×610=1880=940P=\dfrac38\times\dfrac6{10}=\dfrac{18}{80}=\dfrac{9}{40}.

Step 4. Part (iii) -- one white, one black. This happens two ways -- bag 1 white & bag 2 black, OR bag 1 black & bag 2 white: P=(58×610)+(38×410)=3080+1280=4280=2140P=\left(\dfrac58\times\dfrac6{10}\right)+\left(\dfrac38\times\dfrac4{10}\right)=\dfrac{30}{80}+\dfrac{12}{80}=\dfrac{42}{80}=\dfrac{21}{40}. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.