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Question 83 of 89

Q.Four persons are selected at random from a group of 3 men, 2 women and 4 children. The probability that exactly two of them are children is:

(a) 12\dfrac{1}{2}
(b) 34\dfrac{3}{4}
(c) 1021\dfrac{10}{21}
(d) 1023\dfrac{10}{23}
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2025MCQ· 1mImportance★★★★★
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Use the hypergeometric counting approach: favourable ways over total ways.

Total persons =3+2+4=9=3+2+4=9. We want exactly 2 of the 4 selected to be children (from 4 children) and the other 2 from the remaining 5 non-children (3 men + 2 women).

Favourable ways =(42)×(52)=6×10=60=\binom{4}{2}\times\binom{5}{2}=6\times10=60. …

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