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Question 85 of 89

Q.Eight coins are tossed once, find the probability of getting :

(i) exactly two tails
(ii) atmost two tails
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2025Subjective· 3mImportance★★★★★
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Tossing 8 fair coins is a binomial experiment with n=8n=8 and p=12p=\tfrac12; use P(X=k)=(8k)(12)8P(X=k)=\binom8k\left(\tfrac12\right)^8.

Let XX be the number of tails in 8 tosses. X∼Binomial(8,12)X\sim\text{Binomial}(8,\tfrac12), so P(X=k)=(8k)28=(8k)256P(X=k)=\dfrac{\binom8k}{2^8}=\dfrac{\binom8k}{256}.

  1. Exactly two tails: P(X=2)=(82)256=28256=764P(X=2)=\dfrac{\binom82}{256}=\dfrac{28}{256}=\dfrac{7}{64}.
  2. At most two tails: P(X≤2)=P(X=0)+P(X=1)+P(X=2)P(X\leq2)=P(X=0)+P(X=1)+P(X=2). …

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