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Exercise 7.1 · Q21

Q.Construct the matrix A=[aij]3×3A=[a_{ij}]_{3\times3}, where aij=i−ja_{ij}=i-j. State whether AA is symmetric or skew-symmetric.

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We evaluate aij=i−ja_{ij}=i-j for every pair (i,j)(i,j) from 11 to 33 to build the matrix, then check the symmetric/skew-symmetric condition directly on the formula.

Step 1. Compute every entry using aij=i−ja_{ij}=i-j.

a11=1−1=0, a12=1−2=−1, a13=1−3=−2a_{11}=1-1=0,\ a_{12}=1-2=-1,\ a_{13}=1-3=-2

a21=2−1=1, a22=2−2=0, a23=2−3=−1a_{21}=2-1=1,\ a_{22}=2-2=0,\ a_{23}=2-3=-1

a31=3−1=2, a32=3−2=1, a33=3−3=0a_{31}=3-1=2,\ a_{32}=3-2=1,\ a_{33}=3-3=0

Step 2. Assemble the matrix.

A=(0−1−210−1210)A=\begin{pmatrix}0&-1&-2\\1&0&-1\\2&1&0\end{pmatrix}

Step 3. Test the symmetric condition (aij=ajia_{ij}=a_{ji}). E.g. a12=−1a_{12}=-1 but a21=1a_{21}=1 — these are NOT equal, so AA is not symmetric. …

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