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Exercise 7.1 · Q22

Q.Let AA and BB be two symmetric matrices. Prove that AB=BAAB=BA if and only if ABAB is a symmetric matrix.

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Both directions follow from the reversal law (AB)T=BTAT(AB)^T=B^TA^T combined with AT=AA^T=A and BT=BB^T=B (since A,BA,B are symmetric); we prove each implication separately.

Step 1. Record the given facts. Since A,BA,B are symmetric, AT=AA^T=A and BT=BB^T=B.

Step 2. (⇒\Rightarrow) Assume AB=BAAB=BA; show ABAB is symmetric.

By the reversal law, (AB)T=BTAT=BA(AB)^T=B^TA^T=BA (using BT=B, AT=AB^T=B,\ A^T=A).

Since we're given AB=BAAB=BA, this means (AB)T=AB(AB)^T=AB, i.e. ABAB is symmetric.

Step 3. (⇐\Leftarrow) Assume ABAB is symmetric, i.e. (AB)T=AB(AB)^T=AB; show AB=BAAB=BA.

By the reversal law, (AB)T=BTAT=BA(AB)^T=B^TA^T=BA (again using BT=B, AT=AB^T=B,\ A^T=A). …

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