Exercise 7.2 · Q1
Q.Without expanding the determinant, prove that
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✓ Free question
Using makes the third column constant ; it is then proportional to the first column of 's, so the determinant vanishes.
We use the property that a determinant with two proportional columns is zero, together with the fact that a column operation leaves the value unchanged.
Step 1. Apply the column operation (this does not change the value of the determinant):
Step 2. The first column is and the new third column is . Thus and are both scalar multiples of , i.e. they are proportional.
Step 3. A determinant with two proportional columns is . Hence the given determinant is .
✓Final answer
Without expansion, .
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