Exercise 7.2 · Q2
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✓ Free question
Scaling the rows by exposes that column 1 is a linear combination of columns 2 and 3, so the determinant is zero.
We use the property that if one column is a linear combination of the other columns, the determinant is .
Step 1. Multiply by respectively. This multiplies the determinant by , so
Step 2. Take out common from and common from :
Step 3. Observe that , since , and similarly for the other rows. So is a linear combination of and .
Step 4. A determinant whose one column is a linear combination of the others is . Hence , giving .
✓Final answer
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