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Question 106 of 110

Q.Construct an m×nm \times n matrix A=[aij]A = [a_{ij}], where aija_{ij} is given by aij=(i−2j)22a_{ij} = \dfrac{(i-2j)^2}{2} with m=2,n=3m=2, n=3.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2025Subjective· 2mImportance★★★★★
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Substitute each pair (i,j)(i,j) into the formula to build the 2×32\times3 matrix entry by entry.

For m=2,n=3m=2,n=3, the matrix A=[aij]A=[a_{ij}] has i=1,2i=1,2 and j=1,2,3j=1,2,3, with aij=(i−2j)22a_{ij}=\dfrac{(i-2j)^2}{2}.

a11=(1−2)22=12a_{11}=\dfrac{(1-2)^2}{2}=\dfrac12

a12=(1−4)22=92a_{12}=\dfrac{(1-4)^2}{2}=\dfrac92

a13=(1−6)22=252a_{13}=\dfrac{(1-6)^2}{2}=\dfrac{25}2

a21=(2−2)22=0a_{21}=\dfrac{(2-2)^2}{2}=0

a22=(2−4)22=2a_{22}=\dfrac{(2-4)^2}{2}=2 …

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