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Question 94 of 110

Q.If A=[a2abacabb2bcacbcc2]A = \begin{bmatrix} a^2 & ab & ac \\ ab & b^2 & bc \\ ac & bc & c^2 \end{bmatrix} and a2+b2+c2=1a^2+b^2+c^2=1 then find the value of A2A^2.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2020Subjective· 3mImportance★★★★★
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Recognising AA as vvTvv^T for v=(a,b,c)Tv=(a,b,c)^T makes A2=(a2+b2+c2)A=AA^2=(a^2+b^2+c^2)A=A immediate.

Let v=[abc]v=\begin{bmatrix}a\\b\\c\end{bmatrix}. Then the outer product vvTvv^T is:

vvT=[abc][abc]=[a2abacabb2bcacbcc2]=A,vv^T=\begin{bmatrix}a\\b\\c\end{bmatrix}\begin{bmatrix}a&b&c\end{bmatrix}=\begin{bmatrix}a^2&ab&ac\\ab&b^2&bc\\ac&bc&c^2\end{bmatrix}=A,

which is exactly the given matrix.

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