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Exercise 1.3 · Q4

Q.State whether the following relations are functions or not. If it is a function check for one-to-oneness and ontoness. If it is not a function, state why?

(i) If A={a,b,c}A=\{a,b,c\} and f={(a,c),(b,c),(c,b)}f=\{(a,c),(b,c),(c,b)\}; (f:A→Af:A\to A).
(ii) If X={x,y,z}X=\{x,y,z\} and f={(x,y),(x,z),(z,x)}f=\{(x,y),(x,z),(z,x)\}; (f:X→Xf:X\to X).
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Step 1 (i) A={a,b,c}, f={(a,c),(b,c),(c,b)}A=\{a,b,c\},\ f=\{(a,c),(b,c),(c,b)\}. Every element a,b,ca,b,c appears exactly once as a first coordinate, each with one image: a↦c, b↦c, c↦ba\mapsto c,\ b\mapsto c,\ c\mapsto b. Both function conditions hold, so this IS a function.

Step 2. One-to-one? f(a)=c=f(b)f(a)=c=f(b) but a≠ba\ne b -- not one-to-one.

Step 3. Onto? Range ={b,c}=\{b,c\} (the images that occur), but co-domain is A={a,b,c}A=\{a,b,c\}; element aa has no pre-image -- not onto. …

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