Q.Let and . Give a function from for each of the following:
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Start your 14-day free trial to unlock the full solution →Step 1 (i) neither one-to-one nor onto. Take : not injective ( all map to ), and not onto ( have no pre-image).
Step 2 (ii)/(iii) -- checking feasibility first. Both and have exactly 4 elements. For finite sets of EQUAL size, an onto function is automatically one-to-one, and a one-to-one function is automatically onto (pigeonhole: if some two domain elements collapsed onto the same image, at least one of the 4 co-domain elements would be left without a pre-image, since only distinct images could be produced for 4 targets). So a function that is "not one-to-one but onto", or "one-to-one but not onto", cannot exist between two 4-element sets. …
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