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Exercise 1.5 · Q20

Q.If the function f:[−3,3]→Sf:[-3,3]\to S defined by f(x)=x2f(x)=x^2 is onto, then SS is

(1) [−9,9][-9,9]
(2) RR
(3) [−3,3][-3,3]
(4) [0,9][0,9]
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Step 1. As xx ranges over [−3,3][-3,3], x2x^2 attains its minimum 00 (at x=0x=0) and maximum 99 (at x=±3x=\pm3), and by continuity sweeps through every value in between.

Step 2. So the actual range of f(x)=x2f(x)=x^2 on [−3,3][-3,3] is exactly [0,9][0,9]. …

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