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Exercise 1.5 · Q25

Q.The function f:R→Rf:R\to R is defined by
[!FORMULA] f(x)=(x2+cos⁡x)(1+x4)(x−sin⁡x)(2x−x3)+e−∣x∣f(x)=\dfrac{(x^2+\cos x)(1+x^4)}{(x-\sin x)(2x-x^3)+e^{-|x|}}
is

(1) an odd function
(2) neither an odd function nor an even function
(3) an even function
(4) both odd function and even function.
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Step 1 (numerator). N(x)=(x2+cos⁡x)(1+x4)N(x)=(x^2+\cos x)(1+x^4). Since x2,cos⁡x,x4x^2,\cos x,x^4 are all even, N(−x)=((−x)2+cos⁡(−x))(1+(−x)4)=(x2+cos⁡x)(1+x4)=N(x)N(-x)=((-x)^2+\cos(-x))(1+(-x)^4)=(x^2+\cos x)(1+x^4)=N(x) -- NN is even.

Step 2 (denominator, piece by piece). x−sin⁡xx-\sin x: since xx is odd and sin⁡x\sin x is odd, their difference is odd. 2x−x32x-x^3: both 2x2x and x3x^3 are odd, so their difference is odd. The PRODUCT of two odd functions is even, so (x−sin⁡x)(2x−x3)(x-\sin x)(2x-x^3) is even. Adding e−∣x∣e^{-|x|} (even, since ∣−x∣=∣x∣|-x|=|x|) keep …

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