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Question 161 of 175

Q.sin⁡(A−B)cos⁡Acos⁡B+sin⁡(B−C)cos⁡Bcos⁡C+sin⁡(C−A)cos⁡Ccos⁡A\dfrac{\sin(A-B)}{\cos A\cos B}+\dfrac{\sin(B-C)}{\cos B\cos C}+\dfrac{\sin(C-A)}{\cos C\cos A} is:

(a) 00
(b) sin⁡A+sin⁡B+sin⁡C\sin A+\sin B+\sin C
(c) cos⁡A+cos⁡B+cos⁡C\cos A+\cos B+\cos C
(d) 11
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2024MCQ· 1mImportance★★★★★
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The whole sum telescopes to 00.

Using sin⁡(A−B)=sin⁡Acos⁡B−cos⁡Asin⁡B\sin(A-B)=\sin A\cos B-\cos A\sin B:

sin⁡(A−B)cos⁡Acos⁡B=sin⁡Acos⁡B−cos⁡Asin⁡Bcos⁡Acos⁡B=tan⁡A−tan⁡B.\dfrac{\sin(A-B)}{\cos A\cos B}=\dfrac{\sin A\cos B-\cos A\sin B}{\cos A\cos B}=\tan A-\tan B.

Similarly the other two terms give tan⁡B−tan⁡C\tan B-\tan C and tan⁡C−tan⁡A\tan C-\tan A.

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