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Exercise 8.5 · Q1

Q.The value of AB⃗+BC⃗+DA⃗+CD⃗\vec{AB}+\vec{BC}+\vec{DA}+\vec{CD} is

(1) AD⃗\vec{AD}
(2) CA⃗\vec{CA}
(3) 0⃗\vec 0
(4) −AD⃗-\vec{AD}
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✓ Free question

Step 1. Reorder the (commutative) sum: AB⃗+BC⃗+DA⃗+CD⃗=AB⃗+BC⃗+CD⃗+DA⃗\vec{AB}+\vec{BC}+\vec{DA}+\vec{CD}=\vec{AB}+\vec{BC}+\vec{CD}+\vec{DA}.

Step 2. This is exactly the polygon-law sum around the closed path A→B→C→D→AA\to B\to C\to D\to A.

Step 3. Any closed path's total displacement is zero, since it returns to its own starting point.

✓Final answer

AB⃗+BC⃗+DA⃗+CD⃗=0⃗\vec{AB}+\vec{BC}+\vec{DA}+\vec{CD}=\vec0 — option (3).

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