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Question 79 of 113

Q.If a⃗\vec{a} is a non-zero vector and k is a scalar such that ∣ka⃗∣=1|k\vec{a}| = 1 then k is equal to:

(a) 1∣a⃗∣\dfrac{1}{|\vec{a}|}
(b) ∣a⃗∣|\vec{a}|
(c) ±1∣a⃗∣\pm\dfrac{1}{|\vec{a}|}
(d) 11
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2018MCQ· 1mImportance★★★★★
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∣ka⃗∣=∣k∣∣a⃗∣=1|k\vec a|=|k||\vec a|=1 gives ∣k∣=1/∣a⃗∣|k|=1/|\vec a|, so kk can be either +1/∣a⃗∣+1/|\vec a| or −1/∣a⃗∣-1/|\vec a|.

For a scalar kk and vector a⃗\vec a, ∣ka⃗∣=∣k∣⋅∣a⃗∣|k\vec a| = |k|\cdot|\vec a| (magnitude of a scaled vector is the absolute value of the scalar times the vector's magnitude).

Given ∣ka⃗∣=1|k\vec a|=1: ∣k∣⋅∣a⃗∣=1⇒∣k∣=1∣a⃗∣⇒k=±1∣a⃗∣|k|\cdot|\vec a| = 1 \Rightarrow |k| = \dfrac{1}{|\vec a|} \Rightarrow k = \pm\dfrac{1}{|\vec a|}

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