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Physics · Ch 9 — Kinetic Theory of Gases

Root Mean Square Speed (v_rms)

9.2.5

Root Mean Square Speed (v_rms)

Definition. The root mean square speed, vrmsv_{rms}, is defined as the square root of the mean of the squared speeds of every molecule in the gas: vrms=v2‾v_{rms}=\sqrt{\overline{v^2}}. Rearranging equation (9.8), kT=13mv2‾kT=\tfrac13 m\overline{v^2}, the mean square speed is

v2‾=3kTm,(9.17)\overline{v^2} = \frac{3kT}{m}, \qquad (9.17)

so the root mean square speed is

vrms=3kTm=1.73kTm.(9.18)v_{rms} = \sqrt{\frac{3kT}{m}} = 1.73\sqrt{\frac{kT}{m}}. \qquad (9.18)

Writing this in terms of the universal gas constant RR and molar mass MM (using NAk=RN_Ak=R and NAm=MN_Am=M), an equally common and more practical form is

vrms=3RTM.(9.19)v_{rms} = \sqrt{\frac{3RT}{M}}. \qquad (9.19)

What the formula tells you. vrmsv_{rms} is directly proportional to T\sqrt{T} and inversely proportional to M\sqrt{M}: (i) at a fixed temperature, lighter molecules move faster on average than heavier ones -- this is why hydrogen and helium have much higher vrmsv_{rms} than oxygen or nitrogen at the same temperature; and (ii) raising the temperature of any gas always increases the rms speed of its molecules. Equation (9.6) can equivalently be written directly in terms of vrmsv_{rms} as P=13nmvrms2P=\tfrac13 nmv_{rms}^2, since v2‾=vrms2\overline{v^2}=v_{rms}^2 by definition. It is also worth noting explicitly that vrmsv_{rms} is not the same as the average speed -- the average speed of a gas turns out to be about 0.92 times the rms speed (see Section 9.2.6).

Worked illustration (Example 9.2). A room at 27∘27^\circC (T=300T=300 K) contains oxygen and hydrogen molecules in the ratio 3:1 (MO2=32×10−3 kg mol−1M_{O_2}=32\times10^{-3}\ \text{kg mol}^{-1}, MH2=2×10−3 kg mol−1M_{H_2}=2\times10^{-3}\ \text{kg mol}^{-1}, R=8.32 J mol−1K−1R=8.32\ \text{J mol}^{-1}\text{K}^{-1}).

(a) rms speeds: vrms,O2=3×8.32×300/(32×10−3)≈484 m s−1v_{rms,O_2}=\sqrt{3\times8.32\times300/(32\times10^{-3})}\approx484\ \text{m s}^{-1}, and vrms,H2=3×8.32×300/(2×10−3)≈1934 m s−1≈1.93 km s−1v_{rms,H_2}=\sqrt{3\times8.32\times300/(2\times10^{-3})}\approx1934\ \text{m s}^{-1}\approx1.93\ \text{km s}^{-1} -- since the molar mass of oxygen is 16 times that of hydrogen and vrms∝1/Mv_{rms}\propto1/\sqrt M, hydrogen's rms speed is 16=4\sqrt{16}=4 times larger, matching 1934/484≈41934/484\approx4. …