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III. Long Answer Questions · Q11

Q.Calculate the centripetal acceleration of the Moon towards the Earth. (Time period of the Moon's orbit = 27.3 days; radius of the Earth = 6.4×1066.4\times10^6 m; the Moon's orbital radius is 60 times the radius of the Earth)

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Step 1. The centripetal acceleration is a=v2r=ω2ra=\dfrac{v^2}{r}=\omega^2r; it's more convenient to use ω since the Moon's speed is not given directly.

Step 2. The Moon's orbital radius is given as 60 times the Earth's radius: Rm=60×6.4×106 m=3.84×108 mR_m=60\times6.4\times10^6\text{ m}=3.84\times10^8\text{ m}.

Step 3. The angular velocity is ω=2πT\omega=\dfrac{2\pi}{T}, with T=27.3T=27.3 days =27.3×24×3600 s=2.358×106 s=27.3\times24\times3600\text{ s}=2.358\times10^6\text{ s}.

Step 4. So ω=2π2.358×106≈2.664×10−6 rad s−1\omega=\dfrac{2\pi}{2.358\times10^6}\approx2.664\times10^{-6}\text{ rad s}^{-1}. …

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