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Question 26 of 39
Q.

(a) Compute (i) Laspeyre's (ii) Paasche's (iii) Fisher's Index numbers for the year 2010 from the following data.

CommodityPrice 2000Price 2010Quantity 2000Quantity 2010
A12141816
B15162015
C14152420
D12122923

OR

(b) The probability function of a random variable X is given by p(x)={14,for x=−214,for x=012,for x=100,elsewherep(x)=\begin{cases}\dfrac{1}{4}, & \text{for } x=-2 \\ \dfrac{1}{4}, & \text{for } x=0 \\ \dfrac{1}{2}, & \text{for } x=10 \\ 0, & \text{elsewhere}\end{cases}

Evaluate the following probabilities

(i) P(X≤0)P(X\le 0) (ii) P(X<0)P(X<0) (iii) P(∣X∣≤2)P(|X|\le 2) (iv) P(0≤X≤10)P(0\le X\le 10)

Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2023Subjective· 5mImportance★★★★★
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(a) L=106.67, P=106.89, F=106.78L=106.67,\ P=106.89,\ F=106.78. (b) 12, 14, 12, 34\tfrac12,\ \tfrac14,\ \tfrac12,\ \tfrac34.

(a) Index numbers for 2010. Compute the products:

Commodityp0p_0p1p_1q0q_0q1q_1p1q0p_1q_0p0q0p_0q_0p1q1p_1q_1p0q1p_0q_1
A12141816252216224192
B15162015320300240225
C14152420360336300280
D12122923348348276276
Total128012001040973

Laspeyre’s L=∑p1q0∑p0q0×100=12801200×100=106.67.\text{Laspeyre's } L=\frac{\sum p_1q_0}{\sum p_0q_0}\times100=\frac{1280}{1200}\times100=106.67.

Paasche’s P=∑p1q1∑p0q1×100=1040973×100=106.89.\text{Paasche's } P=\frac{\sum p_1q_1}{\sum p_0q_1}\times100=\frac{1040}{973}\times100=106.89.

Fisher’s F=L×P=106.67×106.89=106.78.\text{Fisher's } F=\sqrt{L\times P}=\sqrt{106.67\times106.89}=106.78.

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