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Exercises · Q8

Q.Find the order and degree of d3ydx3+x(dydx)2−y=0\dfrac{d^3y}{dx^3}+x\left(\dfrac{dy}{dx}\right)^2-y=0.

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✓ Free question

Identifying the highest-order derivative

The equation contains d3ydx3\frac{d^3y}{dx^3}, (dydx)2\left(\frac{dy}{dx}\right)^2, and yy. The highest-order derivative present is d3ydx3\frac{d^3y}{dx^3}, so the order is 3.

Identifying the degree

The equation is a polynomial in its derivatives, and d3ydx3\frac{d^3y}{dx^3} appears to the power 11, so the degree is 1. The power 22 on the lower-order dydx\frac{dy}{dx} term does not affect this.

Check (independent recomputation, re-scanning every derivative term present): the only third-order term is d3ydx3\frac{d^3y}{dx^3} with exponent 1; no higher-order term exists — confirms order 3, degree 1.

✓Final answer

Order =3=3, Degree =1=1

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