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Question 27 of 43

Q.The order and degree of the differential equation d2ydx2=dydx+5\sqrt{\frac{d^2y}{dx^2}}=\sqrt{\frac{dy}{dx}+5} are respectively :

(a) 2 and 1
(b) 2 and 3
(c) 2 and 2
(d) 3 and 2
Tamil Nadu DgeTamil Nadu HSC (DGE) Commerce Board 2024MCQ· 1mImportance★★★★★
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Square both sides ⇒d2ydx2=dydx+5\Rightarrow \frac{d^2y}{dx^2}=\frac{dy}{dx}+5; order 22, degree 11.

Starting from d2ydx2=dydx+5\sqrt{\dfrac{d^2y}{dx^2}}=\sqrt{\dfrac{dy}{dx}+5}, square both sides to clear the radicals:

d2ydx2=dydx+5.\frac{d^2y}{dx^2}=\frac{dy}{dx}+5.

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