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Worked Examples · Example 3

Q.The marginal cost of producing xx units is MC=6x+5MC=6x+5 (in ₹ per unit), and the fixed cost is ₹200. Find the total cost function, and the cost of producing 10 units.

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Integrating the marginal cost

C(x)=∫(6x+5) dx=3x2+5x+KC(x)=\int(6x+5)\,dx=3x^2+5x+K

Pinning KK using the fixed cost

Since C(0)=Fixed Cost=200C(0)=\text{Fixed Cost}=200: C(0)=3(0)2+5(0)+K=K=200C(0)=3(0)^2+5(0)+K=K=200.

C(x)=3x2+5x+200C(x)=3x^2+5x+200

Cost of producing 10 units

C(10)=3(10)2+5(10)+200=300+50+200=550C(10)=3(10)^2+5(10)+200=300+50+200=550 …

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