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Worked Examples · Example 5

Q.For the demand function p=30−2xp=30-2x and supply function p=5+3xp=5+3x, find the equilibrium point, and then compute the Consumer's Surplus and Producer's Surplus.

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Finding the equilibrium point

Setting demand equal to supply: 30−2x=5+3x⇒25=5x⇒x0=530-2x=5+3x \Rightarrow 25=5x \Rightarrow x_0=5. Then p0=30−2(5)=20p_0=30-2(5)=20 (checking against supply: 5+3(5)=205+3(5)=20 ✓, both give the same p0p_0).

Consumer's Surplus

CS=∫05(30−2x) dx−x0p0=[30x−x2]05−5(20)CS=\int_0^5(30-2x)\,dx-x_0p_0=\left[30x-x^2\right]_0^5-5(20)

=(150−25)−100=125−100=25=(150-25)-100=125-100=25

Producer's Surplus

PS=x0p0−∫05(5+3x) dx=5(20)−[5x+3x22]05PS=x_0p_0-\int_0^5(5+3x)\,dx=5(20)-\left[5x+\frac{3x^2}{2}\right]_0^5

=100−(25+37.5)=100−62.5=37.5=100-(25+37.5)=100-62.5=37.5 …

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