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Q.The standard deviation of a sample of size 50 is 6.3. Determine the standard error whose population standard deviation is 6.

Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2022Subjective· 2mImportance★★★★★
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Standard error of the mean =σ/n=6/50≈0.85=\sigma/\sqrt{n}=6/\sqrt{50}\approx 0.85.

When the population standard deviation σ\sigma is known, the standard error of the sample mean is

S.E.=σn.\text{S.E.}=\frac{\sigma}{\sqrt{n}}.

Here σ=6\sigma=6 and n=50n=50, so

S.E.=650=67.0711≈0.8485.\text{S.E.}=\frac{6}{\sqrt{50}}=\frac{6}{7.0711}\approx 0.8485. …

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