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Worked Examples · Example 3

Q.A sample of 100 invoices from a firm's ledger has a mean value of Rs. 150 (in hundreds) with a known population standard deviation of Rs. 25 (in hundreds). Construct a 95% confidence interval for the true population mean invoice value.

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Given: xˉ=150\bar{x} = 150, σ=25\sigma = 25, n=100n = 100, confidence level = 95% ⇒Zα/2=1.96\Rightarrow Z_{\alpha/2} = 1.96.

Step 1 - standard error:

SE(xˉ)=σn=25100=2510=2.5SE(\bar{x}) = \dfrac{\sigma}{\sqrt{n}} = \dfrac{25}{\sqrt{100}} = \dfrac{25}{10} = 2.5

Step 2 - margin of error:

1.96×2.5=4.91.96 \times 2.5 = 4.9

Step 3 - confidence interval:

xˉ±4.9=150±4.9=(145.1, 154.9)\bar{x} \pm 4.9 = 150 \pm 4.9 = (145.1,\ 154.9) …

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