Q.Read the following passage and answer the questions that follow. At the school athletics meet, Karan competes in the shot put and Ravi in the javelin. Karan's coach tells him to release the shot at about 40° and from as high a point as he can reach, and reminds him that increasing his release speed matters more than anything else. Ravi's coach tells him to release the javelin at about 32°, and warns him that the wind will affect his throw far more than it affects Karan's.
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Start your 14-day free trial to unlock the full solution →(i) A projectile moves freely under gravity + air resistance after release; the five factors are angle, speed, height of release, gravity, air resistance (plus spin).
(ii) 45^° assumes equal launch and landing heights. Karan releases from shoulder height, above the ground → optimum drops below 45^° (~40^°).
(iii) R ∝ v² ⇒ (12/10)² = 1.44 → 44 % increase in range from a 20 % increase in speed.
(iv) The shot is small, dense, heavy → air resistance negligible. The javelin is long, light, broad and designed to glide → lift and drag dominate, so wind matters hugely.
(i) Define a projectile and name the five factors affecting its trajectory
Definition
A projectile is any body that is thrown, struck, kicked or otherwise projected into the air, and which thereafter travels freely through the air under the influence of gravity and air resistance alone — no propelling force acts on it once it has left the hand, foot or implement.
In sport, projectiles include the shot, discus, javelin and hammer, a football, cricket ball or basketball in flight, and even the athlete's own body during a long jump, high jump or gymnastic vault.
Its path through the air is called its trajectory. For a body affected only by gravity, that path is a parabola; air resistance distorts the parabola, sometimes severely.
The five factors
For a projectile launched and landing at the same height:
R = (v² sin(2θ))/g
- R = horizontal range (m) · v = speed of release (m/s) · θ = angle of release · g = acceleration due to gravity (≈ 9.8 m/s²) Maximum range occurs at θ = 45^° — for equal launch and landing heights.
| # | Factor | Effect on the trajectory |
|---|---|---|
| 1 | Angle of projection (release) | Governs the shape of the flight — high and short, or flat and long. At equal launch/landing height the optimum is 45^°. |
| 2 | Speed / velocity of projection | The most powerful factor: R ∝ v², so range grows with the square of release speed. |
| 3 | Height of projection (release) | A release point above the landing surface adds flight time, adds distance, and lowers the optimum angle below 45^°. |
| 4 | Gravity | Pulls the projectile down throughout flight, curving the path into a parabola; the larger g, the shorter the range. It acts equally on all masses. |
| 5 | Air resistance | Drag opposes motion and shortens flight; for aerodynamic implements it also produces lift. Its size depends on the surface area, shape and speed of the body. |
Spin is a further influence: it can generate lift, produce swerve (the Magnus effect) and stabilise an implement in flight.
(ii) Why Karan is coached to about 40°, not 45°
The 45^° result is not wrong — it is conditional. Look again at the formula. R is maximum when sin(2θ) = 1, i.e. 2θ = 90^°, i.e. θ = 45^°. But that derivation assumes the projectile lands at exactly the height from which it was launched.
The "45^° is best" rule carries a hidden condition: launch height must equal landing height. Break the condition and the answer changes.
In the shot put the condition is plainly broken:
- Karan releases the shot from full arm extension above the shoulder — roughly two metres above the circle.
- The shot lands on the ground, at height zero.
So the shot is released above its landing surface. Two consequences follow, and they are the biomechanical reason:
- Flight time is partly free. Because the shot starts high, gravity has an extra couple of metres to work through before it lands. It stays airborne longer than a level-to-level throw at the same angle would.
- Horizontal velocity therefore becomes the better investment. In a level throw, the only way to buy flight time is to send the shot upward — so half the effort must go into height. Here, some of the flight time has already been paid for by the release height, so it pays to put more of the release speed into the horizontal direction and less into the vertical. And "more horizontal, less vertical" means a lower angle.
Hence the optimum angle falls below 45^°. The higher the release point relative to the distance thrown, the further below 45^° it falls — which is why coaches teach roughly 36°–40° for the shot put. This is also why Karan is told to release from as high a point as he can reach: the height itself adds distance and it is what makes the lower angle correct.
Ravi's javelin sits lower still (about 32^°) because, on top of the release-height effect, the javelin is aerodynamic — it glides, and a flatter release angle exploits that glide.
(iii) The effect of raising release speed from 10 m/s to 12 m/s
With the angle θ and the release height held constant, everything in R = v^2sin(2θ)/g except v is fixed, so
R ∝ v² ⇒ R₂/R₁ = (v₂/v₁)²
- v₁ = 10 m/s (old release speed) · v₂ = 12 m/s (new release speed)
- R₁ = old range · R₂ = new range
Working:
-
Form the speed ratio:
v₂/v₁ = (12 m/s)/(10 m/s) = 1.2
(a 20 % increase in release speed)
-
Square it, because range varies as the square of speed:
R₂/R₁ = (1.2)² = 1.44
-
So the new range is 1.44 times the old range:
R₂ = 1.44 R₁
-
Find the increase:
(R₂ - R₁)/R₁ = 1.44 - 1 = 0.44
-
Convert to a percentage:
Percentage increase = 0.44 × 100 = 44 %
Sanity check with a concrete number: if Karan had been throwing 12 m, his new range is 1.44 × 12 = 17.28 m — an increase of 5.28 m, and 5.28 / 12 = 0.44 = 44%. ✓
Why release speed is called the most important factor
Compare what each factor returns:
| Factor | How range depends on it | Effect of improving it by 20 % |
|---|---|---|
| Release speed | R ∝ v² — squared | Range rises by 44 % |
| Release angle | R ∝ sin(2θ) — and the curve is flat near the optimum | Being a few degrees off the optimum costs very little; there is almost nothing to gain |
| Release height | Adds roughly a proportional bonus to the distance | A useful but modest gain — and largely fixed by the athlete's stature and reach |
The squared term is the whole story. A 20 % improvement in speed does not give 20 % more distance — it gives 44 % more. Doubling the release speed would quadruple the range (2² = 4). No other factor multiplies its benefit like this, and no other factor can be improved as much by training. Angle can be optimised once and then it is done; height is essentially given by the athlete's body. Speed can go on being trained — through strength, power and rate-of-force-development work. That is why every throws coach makes release velocity the priority.
(iv) Why air resistance matters far more to the javelin than to the shot
Air resistance (drag) grows with the surface area presented to the air and with the square of the speed; but whether that force matters depends on how it compares with the implement's weight. So the decisive property is the ratio of surface area to mass — in effect, the implement's density and shape.
| Property | Shot (Karan) | Javelin (Ravi) |
|---|---|---|
| Mass | Heavy — 7.26 kg (senior men) | Light — 800 g (senior men) |
| Shape | Small, smooth metal sphere | Long, slender, broad-bladed shaft |
| Surface area exposed | Very small frontal area | Large surface presented to the airflow |
| Density | Very high | Low for its size |
| Aerodynamic design | None — it is not designed to fly, only to be projected | Deliberately designed as an aerofoil — it is meant to glide |
| Result | Drag is negligible beside its weight; it behaves almost as an ideal projectile on a parabola | Drag and lift are large; the flight is not a simple parabola |
Putting it together: …
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