Q.Complete the following reaction: pentan-2-one (CH3-CH2-CH2-CO-CH3), treated with propane-1,3-diol (HO-CH2-CH2-CH2-OH) in the presence of dry HCl, gives ?
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Start your 14-day free trial to unlock the full solution →Step 1. Pentan-2-one, CH3-CH2-CH2-CO-CH3, is a ketone; propane-1,3-diol, HO-CH2-CH2-CH2-OH, supplies the SAME TWO nucleophilic alcohol oxygens that two SEPARATE methanol molecules supply in the book's own acetal-formation example (Section 12.5.A.3), but here tethered together within one molecule.
Step 2. Under dry HCl catalysis, the ketone's carbonyl oxygen is protonated, activating the carbonyl carbon toward nucleophilic attack.
Step 3. One -OH of the diol attacks intermolecularly first, giving a hemiketal; the resulting hydroxyl is then protonated and leaves as water, generating a resonance-stabilised oxocarbenium ion.
Step 4. Because the diol's SECOND -OH is tethered just three atoms away, it attacks that same cationic carbon INTRAmolecularly (rather than requiring a second separate alcohol molecule, as in the simple two-methanol case), closing a six-membered ring. …
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