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Question 68 of 73

Q.The number of electrons that have a total charge of 9650 coulombs is :

(a) 6.022×10226.022 \times 10^{22}
(b) 6.22×10236.22 \times 10^{23}
(c) 6.022×10−346.022 \times 10^{-34}
(d) 6.022×10246.022 \times 10^{24}
Puducherry TnboardTamil Nadu HSC (DGE) Board 2025MCQ· 1mImportance★★★★★
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The charge carried by one mole of electrons (one Faraday) is 96500 C; dividing the given 9650 C by this Faraday constant gives the number of moles of electrons, which is then converted to a number of electrons using Avogadro's number.

Step 1 — moles of electrons: one Faraday, F=96500 CF = 96500\ C, is the charge of exactly one mole (6.022×10236.022\times10^{23}) of electrons. The number of moles of electrons corresponding to 9650 C is: n=9650 C96500 C mol−1=0.1 moln = \dfrac{9650\ C}{96500\ C\,mol^{-1}} = 0.1\ mol

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