In the reaction: Ethanol --PCl5--> X --alc.KOH--> Y --H2SO4/H2O, 298K--> Z. The 'Z' is a) ethane b) ethoxyetha

Choose the Best Answer · Q12

Q. In the reaction: Ethanol --PCl5--> X --alc.KOH--> Y --H2SO4/H2O, 298K--> Z. The 'Z' is

a) ethane

b) ethoxyethane

c) ethylbisulphite

d) ethanol

Puducherry TnboardTextbookSubjectiveImportance★★★★★

30% · 23/76 Questions

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Step 1. Ethanol + PCl5 substitutes -OH for -Cl, giving X = chloroethane (CH3CH2Cl).

Step 2. Chloroethane + alcoholic KOH undergoes E2 elimination (dehydrohalogenation), giving Y = ethene (CH2=CH2). …

Q.In the reaction: Ethanol --PCl5--> X --alc.KOH--> Y --H2SO4/H2O, 298K--> Z. The 'Z' is