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Write Brief Answer · Q22

Q.What will be the products X and A for the following reaction: acetyl chloride --(i) CH3MgBr

(ii) H3O+--> X --acidified K2Cr2O7--> A?
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Step 1. Acetyl chloride, CH3-COCl, reacting with CH3MgBr: the first equivalent displaces chloride to give acetone (CH3-CO-CH3) as an intermediate ketone in situ.

Step 2. A second equivalent of CH3MgBr then adds to that ketone's carbonyl carbon; acid hydrolysis (H3O+) gives X = 2-methylpropan-2-ol (tert-butyl alcohol), (CH3)3C-OH -- a TERTIARY alcohol, since the carbinol carbon now bears three methyl groups. …

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