Q.Among the transition metals of 3d series, the one that has highest negative M²⁺/M standard electrode potential is
Step 1. Recall the table of standard reduction potentials for the M²⁺ + 2e⁻ → M couple across the first-series transition metals: Ti -1.63 V, V -1.19 V, Cr -0.91 V, Mn -1.18 V, Fe -0.44 V, Co -0.28 V, Ni -0.23 V, Cu +0.34 V, Zn -0.76 V.
Step 2. 'Highest negative' means the most negative numerical value (largest magnitude on the negative side), which corresponds to the strongest reducing metal (loses electrons most readily).
Step 3. Compare only the four elements offered as options: Ti = -1.63 V, Cu = +0.34 V, Mn = -1.18 V, Zn = -0.76 V.
Step 4. Of these four, -1.63 V (titanium) is the most negative -- more negative than Mn's -1.18 V and Zn's -0.76 V, while Cu's value is positive and therefore not negative at all.
(a) Ti
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