Choose the Best Answer · Q7
Q.The correct order of increasing oxidizing power in the series
a) VO₂⁺ < Cr₂O₇²⁻ < MnO₄⁻
b) Cr₂O₇²⁻ < VO₂⁺ < MnO₄⁻
c) Cr₂O₇²⁻ < MnO₄⁻ < VO₂⁺
d) MnO₄⁻ < Cr₂O₇²⁻ < VO₂⁺
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Start your 14-day free trial to unlock the full solution →Step 1. Each species represents the highest common oxo-cation/oxoanion of its element in acidic medium: VO₂⁺ (V in +5), Cr₂O₇²⁻ (Cr in +6), MnO₄⁻ (Mn in +7).
Step 2. Standard electrode potential data (and the chapter's extensive worked oxidation examples) show that MnO₄⁻ is the strongest oxidant of the three -- it is capable of oxidising even oxalic acid, sulphide, nitrite and alcohols under acidic conditions with a 5-electron change down to Mn²⁺, a stronger oxidative jump than dichromate's 6-electron/2-Cr change or vanadate's comparatively milder 1-electron change. …
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