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Exercise 7.5 · Q4

Q.Evaluate: displaystylelimxtofracpi2−dfracsecxtanx\\displaystyle\\lim_{x\\to\\frac{\\pi}{2}^{-}}\\dfrac{\\sec x}{\\tan x}

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As x→π/2−x\to\pi/2^-, sec⁡x→∞\sec x\to\infty and tan⁡x→∞\tan x\to\infty, a ∞∞\tfrac{\infty}{\infty} form; one round of l'Hôpital reduces it to a direct evaluation.

Step 1. Check the form. sec⁡x→+∞\sec x\to+\infty, tan⁡x→+∞\tan x\to+\infty as x→π/2−x\to\pi/2^-: a ∞∞\tfrac{\infty}{\infty} form.

Step 2. Apply l'Hôpital. ddxsec⁡x=sec⁡xtan⁡x\dfrac{d}{dx}\sec x=\sec x\tan x; ddxtan⁡x=sec⁡2x\dfrac{d}{dx}\tan x=\sec^2x. …

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