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Exercise 7.8 · Q5

Q.A rectangular page is to contain 24,textcm224\\,\\text{cm}^2 of print. The margins at the top and bottom of the page are 1.5 cm and the margins at other sides of the page is 1 cm. What should be the dimensions of the page so that the area of the paper used is minimum.

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Write the total page dimensions (print ++ margins) in terms of a single print-width variable, using the print-area constraint, then minimize the total area.

Step 1. Set up. Let the print rectangle be xx (width) by yy (height), with xy=24⇒y=24xxy=24\Rightarrow y=\dfrac{24}{x}.

Page width (margins 11 cm each side) =x+2=x+2; page height (margins 1.51.5 cm top and bottom) =y+3=y+3.

A(x)=(x+2)(y+3)=(x+2)(24x+3)=24+3x+48x+6=30+3x+48x.A(x)=(x+2)(y+3)=(x+2)\left(\frac{24}{x}+3\right)=24+3x+\frac{48}{x}+6=30+3x+\frac{48}{x}.

Step 2. Differentiate and solve A′(x)=0A'(x)=0.

A′(x)=3−48x2=0 ⇒ x2=16 ⇒ x=4 (x>0).A'(x)=3-\frac{48}{x^2}=0\ \Rightarrow\ x^2=16\ \Rightarrow\ x=4\ (x>0).

Step 3. Confirm minimum. …

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