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Question 99 of 162

Q.The projection of i⃗−j⃗\vec{i} - \vec{j} on zz-axis is :

(a) 00
(b) 11
(c) −1-1
(d) 22
Puducherry TnboardTamil Nadu HSC (DGE) Board 2016MCQ· 1mImportance★★★★★
61% · 99/162 Questions
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The vector i⃗−j⃗\vec i-\vec j has zero component along k⃗\vec k, so its projection on the zz-axis is 00.

  1. The projection of a vector r⃗=xi⃗+yj⃗+zk⃗\vec r=x\vec i+y\vec j+z\vec k on the zz-axis equals r⃗⋅k⃗=z\vec r\cdot\vec k=z.
  2. Here r⃗=i⃗−j⃗=1i⃗−1j⃗+0k⃗\vec r=\vec i-\vec j=1\vec i-1\vec j+0\vec k.
  3. So r⃗⋅k⃗=0\vec r\cdot\vec k=0. …

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