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Mathematics · Ch 2 — Complex Numbers

Polar Form of a Complex Number

2.7.1

Polar Form of a Complex Number

Polar coordinates form another set of parameters characterising the vector from the origin to a point z=x+iyz=x+iy, using magnitude and direction instead of horizontal/vertical components. The polar coordinate system has a fixed point OO (the pole) and a horizontal half-line from OO (the initial line or polar axis). For a point PP, if rr is the distance from OO to PP and θ\theta is the angle (measured counter-clockwise from the initial line) to the line OPOP, then (r,θ)(r,\theta) are the polar coordinates of PP.

Superimposing this on the ordinary rectangular system gives

x=rcos⁡θ...(1)y=rsin⁡θ...(2)x=r\cos\theta \qquad\text{...(1)} \qquad\qquad y=r\sin\theta \qquad\text{...(2)}

so any nonzero complex number z=x+iyz=x+iy can be expressed as z=rcos⁡θ+irsin⁡θz=r\cos\theta+ir\sin\theta.

Definition. Let r,θr,\theta be polar coordinates of the point P(x,y)P(x,y) corresponding to z=x+iy≠0z=x+iy\ne0. The polar (trigonometric) form of zz is

z=r(cos⁡θ+isin⁡θ),written for short as z=rcis⁡θ.z=r(\cos\theta+i\sin\theta),\qquad\text{written for short as } z=r\operatorname{cis}\theta.

Here rr is the modulus of zz (the absolute value, as before), and θ\theta is called the argument (or amplitude) of zz, written arg⁡z\arg z.

  • If z=0z=0, θ\theta is undefined — polar coordinates always assume z≠0z\ne0.
  • If z=x+iyz=x+iy has polar coordinates (r,θ)(r,\theta), its conjugate z‾=x−iy\overline z=x-iy has polar coordinates (r,−θ)(r,-\theta).

Squaring and adding (1) and (2) gives r=∣z∣=x2+y2r=|z|=\sqrt{x^2+y^2}; dividing (2) by (1) gives tan⁡θ=y/x\tan\theta=y/x.

General argument vs. principal argument. θ\theta can take infinitely many values, all differing by an integer multiple of 2π2\pi — every value of θ\theta satisfying tan⁡θ=y/x\tan\theta=y/x in the correct quadrant for zz is an argument of zz, and the full set of such values is denoted arg⁡z\arg z. There is a unique value of θ\theta satisfying −π<θ≤π-\pi<\theta\le\pi; this is called the principal argument, Arg⁡z\operatorname{Arg}z. In general, arg⁡z=Arg⁡z+2nπ, n∈Z\arg z=\operatorname{Arg}z+2n\pi,\ n\in\mathbb Z.

To find Arg⁡z\operatorname{Arg}z in practice: compute α=tan⁡−1∣yx∣\alpha=\tan^{-1}\left|\dfrac yx\right| (the reference angle, always taken as the acute angle from the calculator) and then adjust for the quadrant containing z=x+iyz=x+iy:

Quadrantsign of (x,y)(x,y)Arg⁡z\operatorname{Arg}z
I(+,+)(+,+)α\alpha
II(−,+)(-,+)π−α\pi-\alpha
III(−,−)(-,-)−(π−α)-(\pi-\alpha)
IV(+,−)(+,-)−α-\alpha

For instance, the principal argument and (general) argument of 1,i,−1,−i1,i,-1,-i are 0, π2, π (but arg⁡=2nπ+π using the branch just past −π too), −π20,\ \dfrac\pi2,\ \pi\ (\text{but}\ \arg=2n\pi+\pi\text{ using the branch just past }-\pi\text{ too}),\ -\dfrac\pi2 respectively, matching the point's position on the axes.

Properties of arguments (parallel to the modulus properties):

arg⁡(z1z2)=arg⁡z1+arg⁡z2,arg⁡ ⁣(z1z2)=arg⁡z1−arg⁡z2,arg⁡(zn)=narg⁡z,\arg(z_1z_2)=\arg z_1+\arg z_2,\qquad \arg\!\left(\frac{z_1}{z_2}\right)=\arg z_1-\arg z_2,\qquad \arg(z^n)=n\arg z,

and cos⁡θ+isin⁡θ\cos\theta+i\sin\theta has the equivalent alternate forms cos⁡(2kπ+θ)+isin⁡(2kπ+θ), k∈Z\cos(2k\pi+\theta)+i\sin(2k\pi+\theta),\ k\in\mathbb Z (adding any whole number of full turns changes nothing).

Multiplication and division in polar form. If z1=r1(cos⁡θ1+isin⁡θ1)z_1=r_1(\cos\theta_1+i\sin\theta_1) and z2=r2(cos⁡θ2+isin⁡θ2)z_2=r_2(\cos\theta_2+i\sin\theta_2), then, using the cosine/sine angle-addition formulas, …

Figure 2.26Fig 2.26: rectangular coordinates — the complex number $x+iy$ as the position vector $\overrightarrow{OP}$ to $P(x,y)$
Fig. 2.26 — Fig 2.26: rectangular coordinates — the complex number $x+iy$ as the position vector $\overrightarrow{OP}$ to $P(x,y)$

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig 2.26: rectangular coordinates — the complex number x+iyx+iy as the position vector OP→\overrightarrow{OP} to …

Figure 2.27Fig 2.27: polar coordinates — the point $P(r,\theta)$ given by distance $r$ from the pole $O$ and inclination $\theta$ of $OP$ from the initial line
Fig. 2.27 — Fig 2.27: polar coordinates — the point $P(r,\theta)$ given by distance $r$ from the pole $O$ and inclination $\theta$ of $OP$ from the initial line

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig 2.27: polar coordinates — the point P(r,θ)P(r,\theta) given by distance rr from the pole OO and inclination θ\theta of OPOP from the …

Figure 2.28Fig 2.28: polar coordinates superimposed on rectangular — $r=\sqrt{x^2+y^2}$, with $x=r\cos\theta$ along the axis to $M$ and $y=r\sin\theta$ vertical to $P(x,y)$
Fig. 2.28 — Fig 2.28: polar coordinates superimposed on rectangular — $r=\sqrt{x^2+y^2}$, with $x=r\cos\theta$ along the axis to $M$ and $y=r\sin\theta$ vertical to $P(x,y)$

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig 2.28: polar coordinates superimposed on rectangular — r=x2+y2r=\sqrt{x^2+y^2}, with x=rcos⁡θx=r\cos\theta along the axis to MM and y=rsin⁡θy=r\sin\theta vertic …

Figure 2.29Fig 2.29: polar (trigonometric) form $z=r(\cos\theta+i\sin\theta)$ — modulus $r$ as the vector length and argument $\theta$ as the angle from the positive real axis
Fig. 2.29 — Fig 2.29: polar (trigonometric) form $z=r(\cos\theta+i\sin\theta)$ — modulus $r$ as the vector length and argument $\theta$ as the angle from the positive real axis

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig 2.29: polar (trigonometric) form z=r(cos⁡θ+isin⁡θ)z=r(\cos\theta+i\sin\theta) — modulus rr as the vector length and argument θ\theta as the angle from the pos …

Figure 2.30Fig 2.30: principal argument, I-Quadrant — for $z$ in the first quadrant, $\theta=\alpha$ (acute angle $\alpha$ measured from the positive x-axis)
Fig. 2.30 — Fig 2.30: principal argument, I-Quadrant — for $z$ in the first quadrant, $\theta=\alpha$ (acute angle $\alpha$ measured from the positive x-axis)

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig 2.30: principal argument, I-Quadrant — for zz in the first quadrant, θ=α\theta=\alpha (acute angle α\alpha measured from the posi …

Figure 2.31Fig 2.31: principal argument, II-Quadrant — for $z$ in the second quadrant, $\theta=\pi-\alpha$ ($\alpha$ acute angle from the negative x-axis)
Fig. 2.31 — Fig 2.31: principal argument, II-Quadrant — for $z$ in the second quadrant, $\theta=\pi-\alpha$ ($\alpha$ acute angle from the negative x-axis)

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig 2.31: principal argument, II-Quadrant — for zz in the second quadrant, θ=π−α\theta=\pi-\alpha (α\alpha acute angle from the nega …

Figure 2.32Fig 2.32: principal argument, III-Quadrant — for $z$ in the third quadrant, $\theta=\alpha-\pi$ ($\alpha$ acute from the negative x-axis; $\theta$ measured clockwise and negative)
Fig. 2.32 — Fig 2.32: principal argument, III-Quadrant — for $z$ in the third quadrant, $\theta=\alpha-\pi$ ($\alpha$ acute from the negative x-axis; $\theta$ measured clockwise and negative)

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig 2.32: principal argument, III-Quadrant — for zz in the third quadrant, θ=α−π\theta=\alpha-\pi (α\alpha acute from the negative x-axis; θ\theta measured clockw …

Figure 2.33Fig 2.33: principal argument, IV-Quadrant — for $z$ in the fourth quadrant, $\theta=-\alpha$ (acute angle $\alpha$ below the positive x-axis, measured clockwise)
Fig. 2.33 — Fig 2.33: principal argument, IV-Quadrant — for $z$ in the fourth quadrant, $\theta=-\alpha$ (acute angle $\alpha$ below the positive x-axis, measured clockwise)

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig 2.33: principal argument, IV-Quadrant — for zz in the fourth quadrant, θ=−α\theta=-\alpha (acute angle α\alpha below the positive x-axis, measu …