Exercise 2.6 · Q5
Q.Obtain the Cartesian equation for the locus of in each of the following cases:
(i)
(ii) .
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Start your 14-day free trial to unlock the full solution →- is a circle equation in disguise; substitute and expand directly.
- is a difference of two squared-modulus expressions, which telescopes into a linear equation in once expanded via the difference-of-squares identity.
Step 1. (i) Substitute into . , so .
Step 2. (i) Square both sides and expand.
(This is the circle of radius centred at , written in Cartesian form.)
Step 3. (ii) Write and in terms of . and .
Step 4. (ii) Subtract — the terms cancel.
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