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Question 67 of 71

Q.Find the value of tan⁡−1(−3)\tan^{-1}(-\sqrt3).

Puducherry TnboardTamil Nadu HSC (DGE) Board 2025Subjective· 2mImportance★★★★★
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Uses the odd-function property of tan⁡−1\tan^{-1} together with the known standard value tan⁡π3=3\tan\dfrac{\pi}{3}=\sqrt3.

  1. Recall the standard value: tan⁡π3=3\tan\dfrac{\pi}{3}=\sqrt3, and π3\dfrac{\pi}{3} lies in the principal value range (−π2,π2)\left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right) of tan⁡−1\tan^{-1}.
  2. Hence tan⁡−1(3)=π3\tan^{-1}(\sqrt3)=\dfrac{\pi}{3}.
  3. tan⁡−1x\tan^{-1}x is an odd function, i.e. tan⁡−1(−x)=−tan⁡−1(x)\tan^{-1}(-x)=-\tan^{-1}(x) for all real xx. …

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